Solutions and Colligative Properties
Understand colligative properties: boiling point elevation, freezing point depression, osmotic pressure, and Raoult's law.
What Are Colligative Properties?
Colligative properties are physical properties of solutions that depend only on the number of dissolved solute particles, not on their chemical identity. The four colligative properties are vapour-pressure lowering, boiling-point elevation, freezing-point depression, and osmotic pressure.
The underlying cause is the same for all four: dissolved solute particles reduce the tendency of solvent molecules to escape into the vapour phase. Because these effects depend on particle count, electrolytes that dissociate into multiple ions produce a larger colligative effect than the same molality of a nonelectrolyte.
All colligative-property equations use molality (m) rather than molarity because molality is independent of temperature — it is defined as moles of solute per kilogram of solvent, so it does not change as the solution expands or contracts with heating and cooling.
Raoult's Law and Vapour-Pressure Lowering
Raoult’s law states that the vapour pressure of a solvent above a solution equals the mole fraction of the solvent times the vapour pressure of the pure solvent:
Psolution = χsolvent · P°solvent
- χsolvent = mole fraction of the solvent = mol solvent / total mol
- P°solvent = vapour pressure of the pure solvent at that temperature
Because adding a nonvolatile solute reduces χsolvent below 1, the solution’s vapour pressure is always lower than that of the pure solvent. The magnitude of the lowering is ΔP = χsolute · P°solvent.
This vapour-pressure lowering is the root cause of boiling-point elevation and freezing-point depression — all colligative properties trace back to the reduced tendency of solvent molecules to escape into the gas phase.
Boiling-Point Elevation
Adding a nonvolatile solute to a solvent raises its boiling point. Because the solute lowers the vapour pressure, a higher temperature is needed for the vapour pressure to reach atmospheric pressure (the condition for boiling).
The equation: ΔTb = i · Kb · m
- ΔTb = boiling-point elevation (°C)
- i = van’t Hoff factor (number of particles per formula unit)
- Kb = ebullioscopic constant of the solvent (for water, 0.512 °C/m)
- m = molality (mol solute / kg solvent)
The new boiling point = normal boiling point + ΔTb. For example, a 1.00 m aqueous glucose solution (i = 1) boils at 100.00 + (1)(0.512)(1.00) = 100.51 °C. The small size of Kb means boiling-point elevation is a relatively subtle effect in dilute solutions.
Freezing-Point Depression
Adding a solute lowers the freezing point of a solution. Solute particles disrupt the formation of the ordered crystal lattice that defines the solid phase, so a lower temperature is required for the solvent to freeze.
The equation: ΔTf = i · Kf · m
- ΔTf = freezing-point depression (°C)
- Kf = cryoscopic constant of the solvent (for water, 1.86 °C/m)
- m = molality; i = van’t Hoff factor
The new freezing point = normal freezing point − ΔTf. This principle explains why salt (NaCl) is spread on icy roads — the dissolved ions depress the freezing point of water well below 0 °C. A 0.50 m aqueous glucose solution gives ΔTf = (1)(1.86)(0.50) = 0.93 °C, so it freezes at −0.93 °C. Note that Kf for water is roughly four times larger than Kb, making freezing-point depression easier to measure experimentally.
Osmotic Pressure
Osmosis is the net flow of solvent through a semipermeable membrane from a region of lower solute concentration to higher solute concentration. The minimum pressure needed to halt this flow is the osmotic pressure (Π).
The equation: Π = iMRT
- Π = osmotic pressure (atm)
- i = van’t Hoff factor
- M = molarity of the solution (mol/L)
- R = 0.08206 L·atm/(mol·K)
- T = temperature in kelvins
Osmotic pressure is extremely sensitive to solute concentration, making it the preferred colligative property for determining molar masses of large molecules such as proteins, where ΔTb or ΔTf would be immeasurably small. In biology, solutions with equal osmotic pressure are called isotonic; a solution with higher Π is hypertonic; lower is hypotonic. Intravenous (IV) fluids must be isotonic with blood to prevent cell damage.
The van't Hoff Factor
The van’t Hoff factor (i) accounts for the dissociation of electrolytes into multiple particles, which amplifies every colligative effect:
- Nonelectrolytes (e.g., glucose, sucrose): i = 1 — molecules remain intact.
- Strong electrolytes: i equals the total number of ions produced. NaCl → Na+ + Cl−, so i = 2. CaCl2 → Ca2+ + 2 Cl−, so i = 3.
- Weak electrolytes: 1 < i < theoretical maximum, because dissociation is incomplete.
In practice, measured i values for strong electrolytes are slightly less than theoretical due to ion pairing — oppositely charged ions can temporarily associate in solution, reducing the effective particle count. This deviation grows at higher concentrations. For example, 0.10 m NaCl ideally gives ΔTf = (2)(1.86)(0.10) = 0.37 °C, but the measured value is typically about 0.35 °C.
Determining Molar Mass from Colligative Data
Because colligative-property equations link a measurable physical change to the amount of dissolved solute, they can be rearranged to find an unknown molar mass. The general strategy is:
- Measure the colligative effect (ΔTb, ΔTf, or Π).
- Use the appropriate equation to calculate molality (or molarity for Π).
- From molality and the known mass of solute and solvent, calculate moles of solute.
- Divide the mass of solute (in grams) by the moles to get the molar mass.
Freezing-point depression is commonly used for small molecules because Kf is large enough to give measurable temperature changes. For macromolecules such as proteins or polymers, osmotic pressure is preferred — even very dilute solutions generate measurable Π values, allowing accurate molar-mass determinations where ΔT methods would fail.
Colligative Property Problem Workflow and Common Mistakes
A reliable workflow for colligative property calculations:
- Determine the solute type: molecular (i = 1) or electrolyte (i = number of ions produced per formula unit).
- Calculate molality (not molarity) using moles of solute per kilogram of solvent.
- Select the correct equation: ΔTb = iKbm for boiling-point elevation, ΔTf = iKfm for freezing-point depression, Π = iMRT for osmotic pressure.
- Apply the van ’t Hoff factor. For strong electrolytes, i equals the number of ions per formula unit (NaCl → i = 2, CaCl2 → i = 3).
- Check the direction: boiling points go up, freezing points go down. If your ΔT has the wrong sign relative to the pure solvent, recheck.
Common mistakes: using molarity instead of molality for boiling-point and freezing-point equations, forgetting the van ’t Hoff factor for ionic solutes (this can double or triple the expected effect), treating a weak electrolyte as though it fully dissociates, and confusing the new boiling/freezing point with the ΔT value itself.
Learning Objectives
After studying this topic, you should be able to:
- Calculate boiling point elevation
- Calculate freezing point depression
- Calculate osmotic pressure
- Apply Raoult's law for vapor pressure lowering
- Account for the van't Hoff factor in electrolyte solutions
Worked Example
Freezing Point Depression with an Electrolyte
Calculate the freezing point of a solution made by dissolving 10.0 g of CaCl2 (molar mass 110.98 g/mol) in 250.0 g of water. Kᶠ for water = 1.86 °C/m.
- Find moles of CaCl2: 10.0 g ÷ 110.98 g/mol = 0.09011 mol.
- Calculate molality: m = 0.09011 mol ÷ 0.2500 kg = 0.3604 m.
- Determine the van’t Hoff factor. CaCl2 → Ca2+ + 2 Cl- produces 3 ions, so i = 3.
- Calculate ΔTᶠ = i · Kᶠ · m = (3)(1.86)(0.3604) = 2.01 °C.
- New freezing point = 0.00 °C − 2.01 °C = −2.01 °C.
The solution freezes at −2.01 °C. The three ions produced by CaCl2 dissociation triple the colligative effect compared to a nonelectrolyte of the same molality.
Self-Study Questions
What is a colligative property and why does it depend only on solute particle count?
What is Raoult’s law and what does it predict?
What is boiling-point elevation and what equation describes it?
What is freezing-point depression and what equation describes it?
Hint: The equation is very similar to the one for boiling-point elevation.
What is osmotic pressure?
What is the van ’t Hoff factor (i) and why does it matter for electrolytes?
How can colligative property data be used to determine the molar mass of an unknown solute?
Why does an ionic solute like NaCl have a greater effect on colligative properties than a molecular solute at the same molality?
What is the difference between an ideal and a non-ideal solution?
Content Sources
Concept sections adapted from open educational resources under Creative Commons licensing:
- OpenStax Chemistry 2e, Ch 11.4: Colligative Properties (CC BY 4.0)