Colligative Properties
Understand colligative properties: boiling point elevation, freezing point depression, osmotic pressure, and Raoult's law.
Chemistry reference tablesWhat Are Colligative Properties?
Colligative properties are physical properties of solutions that depend only on the number of dissolved solute particles, not on their chemical identity. The four colligative properties are vapour-pressure lowering, boiling-point elevation, freezing-point depression, and osmotic pressure.
The underlying cause is the same for all four: dissolved solute particles reduce the tendency of solvent molecules to escape into the vapour phase. Because these effects depend on particle count, electrolytes that dissociate into multiple ions produce a larger colligative effect than the same molality of a nonelectrolyte.
Each colligative-property equation uses a different concentration unit:
- Boiling-point elevation and freezing-point depression use molality (m) — moles of solute per kilogram of solvent. Molality is independent of temperature, which makes it the natural choice when the solution is being heated to its boiling point or cooled to its freezing point.
- Osmotic pressure uses molarity (M) — moles of solute per liter of solution — because the equation Π = iMRT is derived from the same gas-law-style framework that uses volume.
- Raoult’s law uses mole fraction (χ) — the fraction of total moles that the solvent represents.
Converting between molarity, molality, mass percent, and mole fraction (using density to bridge volume and mass) is the subject of T9 LO 9.3 — see T9: Solutions and Concentration for the four-way conversion workflow. This topic assumes you arrive with the right concentration unit for the equation you’re using.
Molality of a saturated solution. Solubility data are usually reported as grams of solute per 100 g of water at a given temperature. Convert that directly to molality by computing moles of solute (mass ÷ molar mass) and dividing by the mass of water in kilograms. Without a measured density of the saturated solution, molarity cannot be inferred from solubility data alone — molality is the natural concentration unit for these problems.
Effective particle concentration. When a strong electrolyte dissolves, the relevant particle count is the sum of every ion released, not the formula-unit count. Each ion concentration equals the formula-unit concentration multiplied by the subscript of that ion in the formula. For 0.250 M CaCl2: [Ca2+] = 0.250 M, [Cl−] = 2 × 0.250 = 0.500 M, total dissolved-particle concentration = 0.750 M. For 0.500 m Al2(SO4)3: [Al3+] = 1.00 m, [SO42−] = 1.50 m, total = 2.50 m. This total is the input to every colligative-property equation below, encapsulated by the van’t Hoff factor i.
Go deeperWhy this matters: road salt and radiator fluid are particle counters
Winter road crews and your car’s cooling system both exploit the central fact of this topic: only the number of dissolved particles matters, not what they are. Salt on an icy road lowers water’s freezing point below the air temperature; ethylene glycol in a radiator works both directions at once, keeping coolant liquid on the coldest morning (freezing-point depression) and unboiled on the hottest climb (boiling-point elevation). Neither substance reacts with the water; each simply shows up in enormous particle numbers. Colligative chemistry is crowd behavior: the solvent responds to how many guests arrived, never to who they are.
Raoult's Law and Vapour-Pressure Lowering
Raoult’s law states that the vapour pressure of a solvent above a solution equals the mole fraction of the solvent times the vapour pressure of the pure solvent:
Psolution = χsolvent · P°solvent
- χsolvent = mole fraction of the solvent = mol solvent / total mol
- P°solvent = vapour pressure of the pure solvent at that temperature
Because adding a nonvolatile solute reduces χsolvent below 1, the solution’s vapour pressure is always lower than that of the pure solvent. The magnitude of the lowering is ΔP = χsolute · P°solvent.
This vapour-pressure lowering is the root cause of boiling-point elevation and freezing-point depression — all colligative properties trace back to the reduced tendency of solvent molecules to escape into the gas phase.
Go deeperWhy dissolved particles lower vapour pressure
The molecular picture behind Raoult’s law is disarmingly simple: evaporation happens only at the surface, and a nonvolatile solute dilutes that surface. Some fraction of the top layer is now occupied by particles that cannot leave, so fewer solvent molecules per second escape into the vapour, while the return traffic (condensation) is unchanged. The equilibrium settles at a lower vapour pressure, in direct proportion to how much of the liquid is still actually solvent: exactly the mole-fraction form of the law.
Every other colligative property on this page is downstream of this one surface-crowding effect.
Boiling-Point Elevation
Adding a nonvolatile solute to a solvent raises its boiling point. Because the solute lowers the vapour pressure, a higher temperature is needed for the vapour pressure to reach atmospheric pressure (the condition for boiling).
The equation: ΔTb = i · Kb · m
- ΔTb = boiling-point elevation (°C)
- i = van’t Hoff factor (number of particles per formula unit)
- Kb = ebullioscopic constant of the solvent (for water, 0.512 °C/m)
- m = molality (mol solute / kg solvent)
The new boiling point = normal boiling point + ΔTb. For example, a 1.00 m aqueous glucose solution (i = 1) boils at 100.00 + (1)(0.512)(1.00) = 100.51 °C. The small size of Kb means boiling-point elevation is a relatively subtle effect in dilute solutions.
Go deeperCommon mistake: salting pasta water to cook faster
The kitchen legend says salted water boils hotter and cooks pasta faster. Run the numbers: a generous tablespoon of salt (about 18 g, or 0.31 mol NaCl) in 4 kg of water gives a molality of 0.078 m, and with i = 2 for NaCl, ΔTb = i·Kb·m = 2 × 0.512 × 0.078 ≈ 0.08 °C: under a tenth of a degree. Your pasta cannot tell.
Salt the water for flavor, which works, not for physics, which does not at kitchen concentrations. Boiling-point elevation is real; the mistake is expecting a colligative effect without a colligative-scale particle count.
Freezing-Point Depression
Adding a solute lowers the freezing point of a solution. Solute particles disrupt the formation of the ordered crystal lattice that defines the solid phase, so a lower temperature is required for the solvent to freeze.
The equation: ΔTf = i · Kf · m
- ΔTf = freezing-point depression (°C)
- Kf = cryoscopic constant of the solvent (for water, 1.86 °C/m)
- m = molality; i = van’t Hoff factor
The new freezing point = normal freezing point − ΔTf. This principle explains why salt (NaCl) is spread on icy roads — the dissolved ions depress the freezing point of water well below 0 °C. A 0.50 m aqueous glucose solution gives ΔTf = (1)(1.86)(0.50) = 0.93 °C, so it freezes at −0.93 °C. Note that Kf for water is roughly four times larger than Kb, making freezing-point depression easier to measure experimentally.
Go deeperWhy this matters: ice cream churns in salted ice
The old-fashioned ice-cream maker is a freezing-point-depression machine: rock salt scattered on the ice jacket dissolves into the meltwater and drags the brine temperature well below 0 °C, cold enough to freeze the cream mixture (which, full of sugar and milk solids, has a depressed freezing point of its own). The same chemistry sets road-salting’s limits: a saturated NaCl brine bottoms out near −21 °C, so below roughly that temperature highway crews switch to calcium chloride or sand, because no amount of extra NaCl can push the freezing point lower than the saturation limit allows.
Osmotic Pressure
Osmosis is the net flow of solvent through a semipermeable membrane from a region of lower solute concentration to higher solute concentration. The minimum pressure needed to halt this flow is the osmotic pressure (Π).
The equation: Π = iMRT
- Π = osmotic pressure (atm)
- i = van’t Hoff factor
- M = molarity of the solution (mol/L)
- R = 0.08206 L·atm/(mol·K)
- T = temperature in kelvins
Osmotic pressure is extremely sensitive to solute concentration, making it the preferred colligative property for determining molar masses of large molecules such as proteins, where ΔTb or ΔTf would be immeasurably small. In biology, solutions with equal osmotic pressure are called isotonic; a solution with higher Π is hypertonic; lower is hypotonic. Intravenous (IV) fluids must be isotonic with blood to prevent cell damage.
Go deeperWhy this matters: IV bags are osmotic engineering
Hospital saline is 0.9% NaCl for an exact reason: that concentration is isotonic with your blood, producing the same osmotic pressure as the fluid inside red blood cells. Drip pure water into a vein instead and osmosis drives water into the cells until they swell and burst; an over-concentrated solution shrivels them by pulling water out. Reverse-osmosis desalination plants run the section’s equation from the other side: they apply pressure greater than seawater’s osmotic pressure (around 27 atm) to force water backwards through the membrane, leaving the salt behind. Π = iMRT prices out both the IV bag and the drinking water.
The van't Hoff Factor
The van’t Hoff factor (i) accounts for the dissociation of electrolytes into multiple particles, which amplifies every colligative effect:
- Nonelectrolytes (e.g., glucose, sucrose): i = 1 — molecules remain intact.
- Strong electrolytes: i equals the total number of ions produced. NaCl → Na+ + Cl−, so i = 2. CaCl2 → Ca2+ + 2 Cl−, so i = 3.
- Weak electrolytes: 1 < i < theoretical maximum, because dissociation is incomplete.
In practice, measured i values for strong electrolytes are slightly less than theoretical due to ion pairing — oppositely charged ions can temporarily associate in solution, reducing the effective particle count. This deviation grows at higher concentrations. For example, 0.10 m NaCl ideally gives ΔTf = (2)(1.86)(0.10) = 0.37 °C, but the measured value is typically about 0.35 °C.
Go deeperCommon mistake: counting atoms instead of ions
The van’t Hoff factor counts the pieces a formula unit breaks into, not the atoms it contains. MgSO4 gives i = 2 (one Mg2+, one intact SO42−), not 6: the sulfate ion travels as a single particle, exactly as it has since the nomenclature topic. CaCl2 gives 3; glucose, which never dissociates, stays at 1 no matter how many atoms it holds.
The two-step check: is the solute an electrolyte at all (molecular compounds mostly are not)? If so, how many ions per formula unit, keeping every polyatomic ion whole? Answer those two and i falls out correctly every time.
Determining Molar Mass from Colligative Data
Because colligative-property equations link a measurable physical change to the amount of dissolved solute, they can be rearranged to find an unknown molar mass. The general strategy is:
- Measure the colligative effect (ΔTb, ΔTf, or Π).
- Use the appropriate equation to calculate molality (or molarity for Π).
- From molality and the known mass of solute and solvent, calculate moles of solute.
- Divide the mass of solute (in grams) by the moles to get the molar mass.
Freezing-point depression is commonly used for small molecules because Kf is large enough to give measurable temperature changes. For macromolecules such as proteins or polymers, osmotic pressure is preferred — even very dilute solutions generate measurable Π values, allowing accurate molar-mass determinations where ΔT methods would fail.
From molar mass to molecular formula. Once colligative measurement gives the molar mass, a separate step combines it with percent composition to identify the molecular formula. The workflow: (1) percent composition → mole ratio of each element per 100 g → empirical formula and its empirical molar mass; (2) molecular molar mass ÷ empirical molar mass = n (a small whole number); (3) multiply empirical subscripts by n. Worked example: an organic compound with composition 93.46% C / 6.54% H gives the empirical formula C6H5 (empirical MW 77.10 g/mol). If the colligative-property data yields a molar mass of 154.2 g/mol, then n = 154.2 / 77.10 = 2.00, so the molecular formula is (C6H5)2 = C12H10 (biphenyl). For pure elements like sulfur, the molar mass is divided by the atomic mass to recover the allotrope subscript n (e.g., MW ≈ 256 g/mol ÷ 32.07 g/mol = 8, identifying S8). The empirical-formula-to-molecular-formula derivation itself is the subject of T8: The Mole and Chemical Formulas — this topic uses it as the closing step in colligative-property molar-mass problems that ask for the molecular formula.
Go deeperWhy this matters: weighing molecules with a thermometer
Before mass spectrometers, this section’s rearrangement was a primary way to weigh a molecule: dissolve a known mass of the mystery compound, measure how far the freezing point drops, and the molality (hence moles, hence molar mass) falls out. Generations of newly discovered compounds got their molar masses from a thermometer and a balance.
The method is not just history. Osmotic pressure, the most sensitive colligative effect, is still used to estimate molar masses of polymers and proteins: molecules so heavy that a solution’s freezing point barely moves, while its osmotic pressure remains comfortably measurable.
Colligative Property Problem Workflow and Common Mistakes
A reliable workflow for colligative property calculations:
- Determine the solute type: molecular (i = 1) or electrolyte (i = number of ions produced per formula unit).
- Calculate molality (not molarity) using moles of solute per kilogram of solvent.
- Select the correct equation: ΔTb = iKbm for boiling-point elevation, ΔTf = iKfm for freezing-point depression, Π = iMRT for osmotic pressure.
- Apply the van ’t Hoff factor. For strong electrolytes, i equals the number of ions per formula unit (NaCl → i = 2, CaCl2 → i = 3).
- Check the direction: boiling points go up, freezing points go down. If your ΔT has the wrong sign relative to the pure solvent, recheck.
Common mistakes: using molarity instead of molality for boiling-point and freezing-point equations, forgetting the van ’t Hoff factor for ionic solutes (this can double or triple the expected effect), treating a weak electrolyte as though it fully dissociates, and confusing the new boiling/freezing point with the ΔT value itself.
Key Equations
Learning Objectives
After studying this topic, you should be able to:
- Calculate boiling-point elevation and freezing-point depression for a solution
- Calculate osmotic pressure of a solution using π = iMRT
- Apply Raoult's law to calculate the vapor-pressure lowering of a solution
- Use the van 't Hoff factor (i) to account for dissociation of electrolytes in colligative-property calculations
- Determine the molar mass of a solute from colligative-property measurements
How-To Procedure
How to Calculate the Freezing Point of a Solution
- Determine whether the solute is a nonelectrolyte (i = 1) or an electrolyte, and find its van't Hoff factor (i = number of ions produced per formula unit).
- Calculate the molality of the solution: m = moles of solute / kilograms of solvent.
- Apply the freezing-point depression equation: ΔTf = iKf m.
- Subtract ΔTf from the normal freezing point of the pure solvent to get the new freezing point.
- Verify the result: the solution should freeze at a lower temperature than the pure solvent.
Worked Example
Freezing Point Depression with an Electrolyte
Calculate the freezing point of a solution made by dissolving 10.0 g of CaCl2 (molar mass 110.98 g/mol) in 250.0 g of water. Kᶠ for water = 1.86 °C/m.
- Find moles of CaCl2: 10.0 g ÷ 110.98 g/mol = 0.09011 mol.
- Calculate molality: m = 0.09011 mol ÷ 0.2500 kg = 0.3604 m.
- Determine the van’t Hoff factor. CaCl2 → Ca2+ + 2 Cl- produces 3 ions, so i = 3.
- Calculate ΔTᶠ = i · Kᶠ · m = (3)(1.86)(0.3604) = 2.01 °C.
- New freezing point = 0.00 °C − 2.01 °C = −2.01 °C.
The solution freezes at −2.01 °C. The three ions produced by CaCl2 dissociation triple the colligative effect compared to a nonelectrolyte of the same molality.
Test Your Understanding
Two aqueous solutions have the same molality: one contains glucose (C6H12O6) and the other contains sodium chloride (NaCl). Which solution will have the lower freezing point, and by approximately what factor will the effects differ?
Self-Study Questions
What is a colligative property and why does it depend only on solute particle count?
What is Raoult’s law and what does it predict?
What is boiling-point elevation and what equation describes it?
What is freezing-point depression and what equation describes it?
Hint: The equation is very similar to the one for boiling-point elevation.
What is osmotic pressure?
What is the van ’t Hoff factor (i) and why does it matter for electrolytes?
How can colligative property data be used to determine the molar mass of an unknown solute?
Why does an ionic solute like NaCl have a greater effect on colligative properties than a molecular solute at the same molality?
What is the difference between an ideal and a non-ideal solution?
Content Sources
Concept sections adapted from open educational resources under Creative Commons licensing:
- OpenStax Chemistry 2e, Ch 11.4: Colligative Properties (CC BY 4.0)